Question

How do you calculate the ionic strength of 0.0087 M NaOH?

Answer 1

The ionic strength of 0.0087 mol/L NaOH is 0.0087 mol/L.

Explanation:

The molar ionic strength, I, of a solution is a function of the concentration of all ions in that solution.

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯∣∣ ∣∣aaI=12n∑i=1ciz2iaa∣∣ ∣∣−−−−−−−−−−−−−−−−−

where

ci is the molar concentration of ion i

zi is the charge on that ion

and the sum is taken over all ions in the solution.

∴ I=12[0.0087 mol/L×(+1)2+0.0087 mol/L×(-1)2]=0.0087 mol/L

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