How do you compute the intercepts of a quadratic function?
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y = a x² + b x + c = f (x) a generic quadratic function.
y intercept is when x = 0, so y intercept is c.
x intercepts are two. when y =0 = f(x).
then the intercepts are α = [ - b + √(b² - 4 ac) ] / 2 a ,
β = [ - b - √(b² - 4ac) ] / 2 a
y intercept is when x = 0, so y intercept is c.
x intercepts are two. when y =0 = f(x).
then the intercepts are α = [ - b + √(b² - 4 ac) ] / 2 a ,
β = [ - b - √(b² - 4ac) ] / 2 a
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