Question

How do you condense ln3−2ln(9+3)?

Answer 1

This is answer of your question-

$ln(3) - 2 ln(9 + 3) \\ ln(3) - ln( {(9 + 3)}^{2} ) \\ ln(3) - ln(144) \\ using \: property \: log(a) - log(b) = log( \frac{a}{b} ) \\ ln( \frac{3}{144} )$

Hope it will help you!!

Answer 2

$\sf \ln(3) - 2 \ln(9 + 3)$

$\sf = \ln(3) - \ln( {(12)}^{2} )$

$\sf = \ln(3) - \ln(144)$

$\sf = \ln( \frac{3}{144} )$

$\sf = \ln( \frac{1}{48} )$

$\sf = \ln( {48}^{ - 1} )$

$\sf = - 1\ln(48)$

This is your required answer.