Question

How do you determine d2ydx2 given sinx−4cosy=y?

Answer 1

Now d2y/dx2 = (2y —1) dy/ dx = (2y —l)(y —3)(y + 2). so the .... we obtain cscy ' scc^x z :-osy = —x —|sin 2x + c or 4cosy = 2x + sin .... z z Using y(l) = 0