Question

How do you differentiate (14−3t)+(3t(4−3t)2)?

Answer 1

y'=−2t5−8t3+14t(t4−3t2+1)2. Explanation: We know the following rule for the derivative of the ratio: y=f(t)g(t)→y'=f'(t)⋅g(t)−f(t)⋅g'( t)g2(t).