How do you differentiate g(x)=xcosx?
Answers
Answered by
0
⚫️ Step-by-step explanation of the solution :
On differenciating both sides we get...
g'(x)=d/dx(x).cosx+d/dx(cos x).x
g'(x)=1.cosx+(-sinx).x
g'(x) = cos x - x sinx
✌✌✌✌✌✌
HOPE IT HELPS...
Answered by
0
Hi mate☺️,by product rule answer is -xsinx+ cosx .ask doubts in comments .mark answer as brainlist.
Attachments:
Similar questions