How do you differentiate sinx−siny=x−y−5?
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Answer:dy/dx = (1-cosx) /(1-cosy)
Step-by-step explanation:
sinx - siny= x - y -5
Simply we diff w.r.t 'x'(if you want you also diff w.r.t 'y')
cosx-(cosy (dy/dx))=1-(dy/dx)-0
Now arrange it
-cosy(dy/dx)+(dy/dx) =1-cosx
dy/dx(1-cosy)=1-cosx
Now we are at end
dy/dx = (1-cosx) /(1-cosy)
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