How do you differentiate y=(2xx−1)(3x+45x2−7)?
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y = (2x^2 -1)(3x+90x-7)
y = (2x^2 -1)( 93x-7)
y = 186x^3 -14x^2 -93x +7
differentiate of this is
dy/dx = d(186x^3-14x^2-93x+7)/dx
= 186×3x^2 -14×2x -93
= 558x^2 -28x -93
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y = (2x^2 -1)( 93x-7)
y = 186x^3 -14x^2 -93x +7
differentiate of this is
dy/dx = d(186x^3-14x^2-93x+7)/dx
= 186×3x^2 -14×2x -93
= 558x^2 -28x -93
This is required answer
.
.
.
.
.
.
HOPE IT HELPS YOU
MARK AS BRAINLIST PLZ
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