Question

How do you divide (x3−6x−25x−18)÷(x+2)?

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$\frac{x {}^{3} - 6x {}^{2} - 25x - 18}{x + 2} \\ \\ = \frac{x {}^{3} + x {}^{2} - 7x {}^{2} - 7x - 18x - 18 }{x + 2} \\ \\ = \frac{x {}^{2}(x + 1) - 7x(x + 1) - 18(x + 1) }{x + 2} \\ \\ = \frac{(x + 1)(x {}^{2} - 7x - 18) }{x + 2} \\ \\ = \frac{(x + 1)(x {}^{2} - 9x + 2x - 18) }{x + 2} \\ \\ = \frac{(x + 1)(x(x - 9) + 2(x - 9)}{x + 2} \\ \\ = \frac{(x + 1)(x + 2)(x - 9)}{x + 2 } \\ \\ = (x + 1)(x - 9) \\ \\ hope \: it \: helps...$