Question

How do you evaluate (2g−1)2−2g+g2 for g = 3?

Answer 1

Answer:

Step-by-step explanation:

(2g - 1)2 - 2g + g²

Where g = 3

(2×3 - 1)2 -2×3 + (3)²

(6-1)2 - 6 + 9

5×2 - 6 + 9

10 - 3 = 7

Hope it works

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