How do you evaluate the function f(x)=3x2+3x−2 for f(2a)?
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Answer:
Step-by-step explanation:
f(x)=3x2+3x−2
f(2a) = 3 [2a]^2 + 3[2a] - 2
= 3 [ 4a^2] + 6a - 2
= 12a^2 +6a - 2
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f(x) = 3x² + 3x - 2
here f = 2a
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