Question

How do you evaluate the function h(x)=.2x2−.6x−.25 for h(−12)?

Answer 1

Answer:

h(-12)=335

Step-by-step explanation:

h(x)=.2x²−.6x−.25

putting x=-12

h(-12)=2*(-12)²-6*(-12)-25

=2*(-12)*(-12)+6*12-25

=2*12*12+6*12-25

=2*144+72-25

=288+72-25

=360-25

=335