Question

How do you evaluate the function j(x)=x3−7x when x=3?

Answer 1

Solution:

Given j(x) = x³-7x

If x = 3 then

value of j(3) = 3³ - 7×3

= 27 - 21

= 6

Therefore,

j(3) = 6

•••

Answer 2

Hey !

Refer the below attachment !

Thanks!