Math, asked by pranayaxis4074, 11 months ago

How do you evaluate the limit (2y2+2y+46y−3)13 as y approaches 5?

Answers

Answered by tasmya
0

Answer:

= [ 2(5)2 +2(5) + 46(5) - 3 ] 13

= [ 20 + 10 + 230 - 3 ] 13

= 257 × 13

= 3341  ................... is the answer.

Hope it helped you.

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