Question

How do you factor 3x2+9x−12=0?

Answer 1

3x²+9x-12=0

3(x²+3x-4)=0

x²+3x-4=0

x²+4x-x-4=0

(x+4)(x-1)=0

x=-4,1

Answer 2

$3x ^{2} + 9x - 12$

$3(x ^{2} + 3x - 4)$

$3(x ^{2} + (4 - 1)x - 4)$

$3(x ^{2} + 4x - x - 4)$

$3{x(x + 4) - 1(x + 4)}$

$(x + 4)(3x - 1)$