How do you factor 3y^4-2y^2-5 completely?
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Answer:
(y²+1)(3y²-5)
Step-by-step explanation:
3y^4-2y^2-5
= 3(y²)²-2(y)²-5
let y² be replaced with x
= 3x²-2x-5
= 3x²+3x-5x-5
= 3x(x+1)-5(x+1)
= (x+1)(3x-5)
putting original value
(y²+1)(3y²-5)
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