How do you factor 42r² -3rt - 9t²?
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Answered by
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Solution:
Given 42r²-3rt-9t²
= 3(14r²-rt-3t²)
= 3( 14r²-7rt+6rt-3t²)
= 3[7r(2r-t)+3t(2r-t)]
= 3(2r-t)(7r+3t)
Therefore,
42r²-3rt-9t² = 3(2r-t)(7r+3t)
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Hey!
Refer the below attachment !
Thanks !
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