How do you factor 42x2+35x+7?
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Answered by
2
Answer:
Step-by-step explanation:
42 x^2+42x-7x+7
42x (x+1)-7 (x+1)
(x+1)(42x-7)
Answered by
2
42x^2+35x+7
taking 7 common , we have
7(6x^2+5x+1)=0
6x^2+5x+1=0
6x^2+3x+2x+1
3x(2x+1)+1(2x+1)
(3x+1)(2x+1)=0
3x+1=0
x=-1/3
2x+1=0
x=-1/2
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