Question

How do you factor 8x^3+4x^2-18x-9?

Answer 1

$8x ^{3} + 4x ^{2} - 18x - 9$

$4x ^{2} (2x + 1) - 9(2x + 1)$

$(2x + 1)(4x ^{2} - 9)$

$(2x + 1)(2x - 3)(2x + 3)$