How do you factor and find the zeroes for F(x)=x3+x2+4x+4?
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F(-1) = (-1)^3 + (-1)^2 + 4(-1) + 4
F(-1) = -1 + 1 - 4 + 4
F(-1) = 0
x^2( x+1) + 4(x+1)
= ( x^2 + 4 ) ( x + 1)
the zeros are -
-1 (the other value will be imaginary)
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