How do you factor completely 6c^2-33c+15?
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Step-by-step explanation:
6c²-33c+15 = 0
6c²-30c-3c+15 = 0
6c(c-5) - 3(c-5) = 0
(6c-3) (c-5) = 0
c = 3/6 or c = 5
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