Question

How do you factor completely 6c^2-33c+15?

Answer 1

Answer:

Step-by-step explanation:

6c²-33c+15 = 0

6c²-30c-3c+15 = 0

6c(c-5) - 3(c-5) = 0

(6c-3) (c-5) = 0

c = 3/6 or c = 5