Question

How do you factor h(x)=x4+4x3+x2−6x?

Answer 1

Four solutions were found :
1.  x = 1
2. x = -2
3. x = -3
4. x = 0


Changes made to your input should not affect the solution:

 (1): "x2"   was replaced by   "x^2".  2 more similar replacement(s).

Step by step solution :

Step  1  :

Equation at the end of step  1  :

(((x4) + 22x3) + x2) - 6x = 0

Step  2  :

Step  3  :

Pulling out like terms :

 3.1     Pull out like factors :

   x4 + 4x3 + x2 - 6x  = 

  x • (x3 + 4x2 + x - 6) 

Checking for a perfect cube :

 3.2    x3 + 4x2 + x - 6  is not a perfect cube 

Trying to factor by pulling out :

 3.3      Factoring:  x3 + 4x2 + x - 6 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  x - 6 
Group 2:  x3 + 4x2 

Pull out from each group separately :

Group 1:   (x - 6) • (1)
Group 2:   (x + 4) • (x2)

Answer 2

Here’s your answer with complete explanation.

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