How do you factor x^7 - 16x^5 + 5x^4 - 80x^2?
Answers
Answered by
0
Answer:
x²(x+4)(x-4)(x+∛5)(x²-∛5x+∛25)
Step-by-step explanation:
x^7 - 16x^5 + 5x^4 - 80x^2
= x²{(x^5-16x^3)+(5x^2-80)}
= x²{x³(x²-16)+5(x²-16)}
= x²(x²-16)(x³+5)
= x²{(x)²-(4)²}{(x)³+(∛5)³}
= x²(x+4)(x-4)(x+∛5)(x²-∛5x+∛25)
Similar questions
Math,
7 months ago
English,
7 months ago
Business Studies,
1 year ago
Business Studies,
1 year ago
Computer Science,
1 year ago