How do you factor −x2y2+x4+4y2−4x2?
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Trying to find out where the common term (here, x2-y2) is the best way to solve this kind of questions
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Solution:
-x²y²+x⁴+4y²-4x²
= (-x²)(y²-x²)+4(y²-x²)
= (y²-x²)(-x²+4)
=(y²-x²)(2²-x²)
= (y+x)(y-x)(2+x)(2-x)
Therefore,
-x²y²+x⁴+4y²-4x²
=(y+x)(y-x)(2+x)(2-x)
••••
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