How do you find all the zeros of f(x)=−4x8−9x7+9x−4 with its multiplicities?
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Here we have to find zero of f(x).So we will put —4x8—9x7+9x—4=0.
So,
—4x8—9x7+9x—4=0
—32—63+9x—4=0
9x—99=0
9x=99
x=99/9=11
Hence,11 is a zero of f(x)=—4x8—9x7+9x—4
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