Math, asked by Chahat239, 1 year ago

How do you find dydx given 2xy+y2=x+y?

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Answered by SirSumit

2

2(x'y+yx')+2yy'=1+y'

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Answered by mahender99

0

2xy+2y=x+y

2xy+2y-x-y=0

2xy+y=x

y(2x+1)=x

y=x/(2x+1)

dy/dx=(2x+1)d/dx (x)-(x)d/dx (2x+1) whole divide by (2x+1) whole square

dy/dx=2x+1-2x/(2x+1) whole square

dy/dx=1/(2x+1) whole square

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