How do you find dydx given 3y3+2=2x?
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Answered by
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<>3y^3 + 2=2x
<>d(3y^3) /dx + d(2) /dx =d(2x)/dx
<>3×3y^2dy/dx + 0 =2
hence answer to this question is
9y^2dy/dx-2=0
remember diffrentiation of constant value is always zero
<>d(3y^3) /dx + d(2) /dx =d(2x)/dx
<>3×3y^2dy/dx + 0 =2
hence answer to this question is
9y^2dy/dx-2=0
remember diffrentiation of constant value is always zero
rockingdude:
hlw
Answered by
1
9ydy = 2xdx dy/dx = 2x/9y
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