How do you find (f of g of h) given f(x)=x2+1 g(x)=2x and h(x)=x−1?
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Answer:
=4x²-8x+5
Step-by-step explanation:
h(x)=x-1
g(x)=2x
g(h(x))=2(x-)=2x-2
Now f(x)=x²+1
f(g(h(x)))=(2x-2)²+1
=4x²-8x+4+1
=4x²-8x+5
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