How do you find (gh)(a) given g(a)=−3a2−a and h(a)=−2a−4?
Answers
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We can remove the negatives by multiplying the result by the appropriate form of
1
:
(
g
h
)
(
a
)
=
−
1
−
1
×
−
3
a
2
−
a
−
2
a
−
4
(
g
h
)
(
a
)
=
−
1
(
−
3
a
2
−
a
)
−
1
(
−
2
a
−
4
)
(
g
h
)
(
a
)
=
3
a
2
+
a
2
a
+
4
If necessary, we can factor the numerator and denominator as:
(
g
h
)
(
a
)
=
a
(
3
a
+
1
)
2
(
a
+
2
)
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