How do you find Sn for the arithmetic series given a1=3, d=-4, n=8?
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a=3,d=-4,n=8,Sn=?
tn=a+(n-1)×d
tn=3+(8-1)× -4
tn=3+7×-4
tn=3-28
tn=-25
Sn=n/2(a+tn)
Sn=8/2(3-25)
Sn=4×-22
Sn=-88
a=3,d=-4,n=8,Sn=?
tn=a+(n-1)×d
tn=3+(8-1)× -4
tn=3+7×-4
tn=3-28
tn=-25
Sn=n/2(a+tn)
Sn=8/2(3-25)
Sn=4×-22
Sn=-88
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