How do you find the differential dy of the function y=2x−cot2x?
Answers
Answered by
0
Hey mate
here is your answer
the derivative of above function is
y' = 2– [–cosec^2(2x)] x2
= 2 [1+ cosec^2(2x)]
HOPE THIS ANSWER
HELPS YOU
Answered by
0
Answer:
For
y
=
f
(
x
)
, the differential of
y
is
d
y
=
f
'
(
x
)
d
x
Explanation:
In this question we have
f
'
(
x
)
=
2
x
−
cot
2
x
so
f
'
(
x
)
=
2
−
2
cot
x
⋅
d
d
x
(
cot
x
)
=
2
−
2
cot
x
⋅
(
−
csc
2
x
)
f
'
(
x
)
=
2
+
2
cot
x
csc
2
x
And so,
d
y
=
(
2
+
2
cot
x
csc
2
x
)
d
x
Similar questions