How do you find the dimensions of a rectangle given the perimeter?
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Let ABCD be a rectangle in a given circle of radius a with centre at O. Let AB = 2x and AD = 2y be the sides of the rectangle. Then,
AM2 + OM2 = OA2 [ Δ OAM is a right angles triangle]
⇒ x2 + y2 = a2

Let P be the perimeter of the rectangle ABCD. Then,
P = 4x + 4y


For maximum or minimum, values of P, we have

Now,

Thus, P is maximum when 
Putting  in (1), we obtain . Therefore, 
Hence, P is maximum when the rectangle is square of side 
AM2 + OM2 = OA2 [ Δ OAM is a right angles triangle]
⇒ x2 + y2 = a2

Let P be the perimeter of the rectangle ABCD. Then,
P = 4x + 4y


For maximum or minimum, values of P, we have

Now,

Thus, P is maximum when 
Putting  in (1), we obtain . Therefore, 
Hence, P is maximum when the rectangle is square of side 
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