Question

How do you find the discriminant for 0.5x2−2x=−2 and determine the number and type of solutions?

Answer 1

Answer:

Step-by-step explanation:

0.5x² - 2x. = -2

0.5x² - 2x + 2 = 0

À = 0.5 , b = -2 , c = 2

Discriminat = b² - 4ac

(-2)² - 4×0.5 × 2

4 - 4 = 0

So thé roots are real nd equal

And There exists two roots

Hope it helps

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