Question

How do you find the equation of a line that Contains points (4, -1) and (-2, -13)?

Answer 1

it is super easy,

use the two point line equation formula,

x-x1/x2-x1=y-y1/y2-y1

so points are (4,-1);(-2,-13)

x-4/-2-4=y+1/-13+1

x-4/-6=y+1/-12

-12x+48=-6y-6

12x-6y=54

2x-y=9

hope this helps