Question

How do you find the equation of the normal to the circle x2+y2=40 at the point (6,2)?

Answer 1

centre(0,0)

normal passes through the centre

so required normal equation is

$y = \frac{2}{6} x$

$y = \frac{x}{3}$

$x = 3y$

$x - 3y = 0$