How do you find the equation of the tangent line to curve y=x−1x+1, that are parallel to the line x−2y=2?
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x-2y=2
2y=2-x
y=2-x÷2
y=x-1x+1
2-x÷2= x-1x+1
2-x= 2x-x+2
x-2=2
x=4
y= 4-4+4
y=4
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