How do you find the extrema of f(x)=4x3−26x2+16x+1 on [0,3]?
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Putting value f(x)=0 4x3-26x2+16x0+1=12-52+0+1=-39. Now putting value of x=3 4x3-26x2+16x3+1=12-52+48+1 =9
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