How do you find the point of intersection for x+2y=3 and 3x−y=−5?
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We can substitute the second equation directly into the first.
x
2
+
(
x
+
1
)
2
=
1
x
2
+
x
2
+
2
x
+
1
=
1
2
x
2
+
2
x
=
0
2
x
(
x
+
1
)
=
0
x
=
0
and
−
1
y
=
x
+
1
y
=
0
+
1
and
y
=
−
1
+
1
y
=
1
and
y
=
0
The points of intersection are
(
−
1
,
0
)
and
(
0
,
1
)
.
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