Question

How do you find the possible values for a if the points (a,2a-1), (2a+4,3a+9) has a distance of √ 260?

Answer 1

Answer:

sorry I did not know this question answer

Answer 2

Answer:

acorrding to distance formula,

distance between two points (a,b ) and( y,z) is√( a-y)² +(b-z)²

so,here also

(a+4)²+(a+10)²=260

a²+9a-72=0

(a+9)(a-8)=0

a=-9 or 8