Math, asked by gunjansingh5241, 10 months ago

How do you find the product 4n(2n3p2−3np2+5n)+4p(6n2p−2np2+3p)?

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Answers

Answered by mysticd

1

Solution:

4n(2n³p²-3np²+5n)+4p(6n²p-2np²+3p)

= 8n⁴p²-12n²p²+20n²

+ 24n²p²-8np³+12p²

= 8n⁴p²-12n²p²+24n²p²-8np³+20n²+12p²

= 8n⁴p²+12n²p²+8np³+20n²+12p²

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