How do you find the product of this reaction? 6CaO + P₄O₁₀
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Answer:
6CaO + P₄O₁₀ = 2Ca₃(PO₄)2₂
Explanation:
Calcium Oxide +(CaO)Tetraphosphorus Decaoxide (P₄O₁₀)=Tricalcium Phosphate (Ca₃(PO₄)₂)
Calcium Oxide + Tetraphosphorus Decaoxide = Tricalcium Phosphate
Reaction Type
Synthesis
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