Question

How do you find the solution to 2sin2θ−1=0 if 0≤θ<360?

Answer 1

15 degree answers

2sin2*-1=0

2sin2* =1

sin2*=1/2

sin2* =sin30

2* =30

*=15

Answer 2

Answer:

15 degrees answer

Step-by-step explanation:

2Sin2*-1=0

2Sin2*=1

Sin2*=1/2

Sin 2*= Sin30

2* = 30

* = 15