How do you find the solution to 2sin2θ−1=0 if 0≤θ<360?
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15 degree answers
2sin2*-1=0
2sin2* =1
sin2*=1/2
sin2* =sin30
2* =30
*=15
Answered by
0
Answer:
15 degrees answer
Step-by-step explanation:
2Sin2*-1=0
2Sin2*=1
Sin2*=1/2
Sin 2*= Sin30
2* = 30
* = 15
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