How do you find the value of a given the points (6,-7), (a,-4) with a distance of √18?
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Answer:
We can do this by using distance formula
Step-by-step explanation:
(6,-7),(a,-4)=√18
by using distance formula
√(a-6)²+(-4-(-7))²=√18
√a²+36-12a+9=√18
√a²-12a+45=√18
squaring both sides
a²-12a+45=18
a²-12a+45-18=0
a²-12a+27=0
by factorization
a²-9a-3a+27=0
a(a-9)-3(a-9)=0
(a-3)(a-9)=0
a-3=0 . a-9=0
a=3 , a=9
so that value of a will be 3 and 9
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