How do you find the value of r such the points (9,r), (6,3) with slope m=-1/3?
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Solution:
Let A(x1,y1)=(9,r);
B(x2,y2) = (6,3);
slope (m) = -1/3
=>(y2-y1)/(x2-x1) = -1/3
=> (3-r)/(6-9) = -1/3
=> (3-r)/(-3) = -1/3
=> 3-r = (-1/3)(-3)
=> 3-r = 1
=> -r = 1-3
=> -r = -2
=> r = 2
Therefore,.
r=2
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