How do you find the zeros by rewriting the function y=x2+4x+3 in intercept form?
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Step-by-step explanation:
Step 1. Factorize the quadratic function given. This is; x2+4x+3
The product of the factors whose product is 3 and sum is 4,
are + 1 and + 3
Thus giving; In intercept form; y=(x+1)(x+3)
Step 2; To obtain the zeros, we equate y to 0.
y=(x+1)(x+3)=0
Equate each factor to 0 and solve for x
x+1=0, x=−1
x+3=0,x=−3
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