Question

How do you find two consecutive, negative integers whose product is 156?

Answer 1

$\mathfrak{\huge{Hi !}}$

$\sf{Let \:the \:numbers\: be = x\: and \: x + 1}$

=》 x ( x + 1 ) = 156

=》 $\tt{x^{2} + x - 156 = 0}$

By factorisation, the values of x = 12, 13

Since we need both the numbers as negative :

$\sf{NUMBERS= (-12),(-13)}$