Question

How do you find two consecutive odd integers such that 3 times the first integer is 5 more than twice the second?

Answer 1

Solution:

Let x,(x+2) are two consecutive

odd integers.

According to the problem given,

3 times the first integer is 5 more than twice the second

3x = 2(x+2)+5

=> 3x = 2x+4+5

=> 3x-2x = 9

=> x = 9

Therefore,

First odd number (x) = 9

Second odd number (x+2)

= 9+2

= 11

9,11 are required two consecutive odd numbers.

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Answer 2

Hey!

Refer the below attachment !

Thanks !