Question

How do you get the formula,
An = a + nd

(class 11)​

Answer 1

Answer:

arithmetic progression se

Step-by-step explanation:

Tn=a+(n-1)d

a=first term

n=total number

d=common differernce

Tn=last term

Answer 2

Let

d= common difference

a1 = first term

a2 = second term

a3 = third term

.............

An = nth term or last term

d=a2−a1=a3−a2=a4−a3 and so on.

Derivation for an in terms of a1 and d

a1 = a

a2 = a1+d = a+(1-1)d

a3 = a2+d = (a1+d)+d = a+2d = a+(3-1)d

a4 = a3+d = (a1+2d)+d = a+3d = a+(4-1)d

a5 = a4+d = (a1+3d)+d = a+4d = a+(5-1)d

………..

Going by this pattern

………..

An = a + (n - 1)d

This is the only explanation I could think of. Although, I do relate with you xD, I also expected some cool derivation, but wait and watch, in 11th you're gonna have sequence and series, which is basically AP on steroids.

Sorry to disappoint if i coudnt match your expectations :(