Question

How do you graph and state the max/min for f(x)=3x2+4x−5?

Answer 1

Hey mate !!!!!

f(x) = $3x ^{2} + 4x - 5$

First we notice that the function has a positive coefficient for x^2.

Then the fucntion has a minimum values.

Now we will find the derivatives zero.

f'(x) = 4x -5 = 0

4x=5

$x = \frac{5}{4}$

f(5/4) =3(5/4)^2+4(5/4)-5

=3(25/16)+5-5

=75/16

==> The minimum values is f(5/4) = 75/16.....

Hope it helps....

Plz mark it as brainiest...~