Math, asked by karun3147, 11 months ago

How do you graph y=−2+3cos(x−π)?

Answers

Answered by Anonymous
0

Answer:

As below.

Explanation:

Standard form of cosine function is

y

=

A

cos

(

B

x

C

)

+

D

Given :

y

=

3

cos

(

x

π

)

2

A

=

3

,

B

=

1

,

C

=

π

,

D

=

2

Amplitude

=

|

A

|

=

3

Period

=

2

π

|

B

|

=

2

π

1

=

2

π

Phase Shift

=

C

B

=

π

1

=

π

,

π

to the LEFT

Vertical Shift

=

D

=

2

graph{3 cos (x - pi) - 2 [-10, 10, -5, 5]}

Answered by riya244567
1
Explanation:

Standard form of cosine function is y=Acos(Bx−C)+D

Given : y=3cos(x−π)−2

A=3,B=1,C=π,D=−2

Amplitude =|A|=3

Period =2π|B|=2π1=2π

Phase Shift =−CB=−π1=−π,π to the LEFT

Vertical Shift =D=−2

graph{3 cos (x - pi) - 2 [-10, 10, -5, 5]}








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