How do you graph y=−2+3cos(x−π)?
Answers
Answered by
0
Answer:
As below.
Explanation:
Standard form of cosine function is
y
=
A
cos
(
B
x
−
C
)
+
D
Given :
y
=
3
cos
(
x
−
π
)
−
2
A
=
3
,
B
=
1
,
C
=
π
,
D
=
−
2
Amplitude
=
|
A
|
=
3
Period
=
2
π
|
B
|
=
2
π
1
=
2
π
Phase Shift
=
−
C
B
=
−
π
1
=
−
π
,
π
to the LEFT
Vertical Shift
=
D
=
−
2
graph{3 cos (x - pi) - 2 [-10, 10, -5, 5]}
Answered by
1
Explanation:
Standard form of cosine function is y=Acos(Bx−C)+D
Given : y=3cos(x−π)−2
A=3,B=1,C=π,D=−2
Amplitude =|A|=3
Period =2π|B|=2π1=2π
Phase Shift =−CB=−π1=−π,π to the LEFT
Vertical Shift =D=−2
graph{3 cos (x - pi) - 2 [-10, 10, -5, 5]}
follow me dude and mark me in brainliest
Standard form of cosine function is y=Acos(Bx−C)+D
Given : y=3cos(x−π)−2
A=3,B=1,C=π,D=−2
Amplitude =|A|=3
Period =2π|B|=2π1=2π
Phase Shift =−CB=−π1=−π,π to the LEFT
Vertical Shift =D=−2
graph{3 cos (x - pi) - 2 [-10, 10, -5, 5]}
follow me dude and mark me in brainliest
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